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How Does Aldehyde React with Organolithium?

Published in Alcohol Synthesis 3 mins read

Organolithium reagents react with aldehydes through a nucleophilic addition reaction to the carbonyl group, ultimately forming alcohols. This is a fundamental reaction in organic synthesis, crucial for creating new carbon-carbon bonds.

The Nucleophilic Addition Mechanism

The reaction between an aldehyde and an organolithium reagent involves a two-step process:

  1. Nucleophilic Attack: Organolithium reagents (R-Li), being exceptionally strong nucleophiles, readily attack the highly electrophilic carbon atom of the aldehyde's carbonyl group. The electron-rich alkyl or aryl group (R) from the organolithium adds to the carbonyl carbon, while the pi bond of the carbonyl shifts its electrons to the oxygen, forming an intermediate alkoxide.
  2. Protonation (Workup): The alkoxide intermediate is then protonated, typically by adding a dilute acid (like aqueous HCl or NH4Cl) during a workup step. This protonation converts the alkoxide into the final alcohol product.

This reaction effectively breaks the carbon-oxygen double bond of the aldehyde and forms a new carbon-carbon single bond and a carbon-oxygen single bond (as part of the hydroxyl group).

General Reaction Scheme

Here's a generalized representation of the reaction:

Step 1: Nucleophilic Attack
R-Li + R'-CHO → R'-CH(O-Li)R
(Organolithium + Aldehyde → Lithium Alkoxide Intermediate)

Step 2: Acidic Workup
R'-CH(O-Li)R + H₃O⁺ → R'-CH(OH)R + Li⁺
(Lithium Alkoxide Intermediate + Acid → Alcohol + Lithium Salt)

Product Alcohols Based on Aldehyde Type

The type of alcohol formed depends on the structure of the initial aldehyde:

  • Formaldehyde (Methanal): When formaldehyde (HCHO) reacts with an organolithium reagent, it yields a primary alcohol. This is because formaldehyde has two hydrogen atoms attached to its carbonyl carbon, allowing only one alkyl or aryl group from the organolithium to add.

    • Example: CH₃CH₂-Li + HCHO → CH₃CH₂-CH₂OH (Propan-1-ol, a primary alcohol)
  • Other Aldehydes (e.g., Acetaldehyde, Propanal): If any other aldehyde (R'CHO, where R' is an alkyl or aryl group) is used, the reaction with an organolithium reagent will produce a secondary alcohol. Here, the carbonyl carbon is bonded to one hydrogen and one R' group, allowing one alkyl or aryl group from the organolithium to add.

    • Example: CH₃-Li + CH₃CHO → CH₃-CH(OH)-CH₃ (Propan-2-ol, a secondary alcohol)

This table summarizes the outcome:

Aldehyde Type Structure Organolithium Reagent (R-Li) Alcohol Product Classification of Alcohol
Formaldehyde HCHO R-Li R-CH₂OH Primary Alcohol
Other Aldehydes R'-CHO R-Li R'-CH(OH)R Secondary Alcohol

Key Considerations for the Reaction

  • Strong Basicity: Organolithium reagents are not only strong nucleophiles but also strong bases. Therefore, the reaction must be performed under anhydrous conditions to prevent the organolithium from reacting with water or other acidic protons instead of the carbonyl group.
  • Aprotic Solvents: The reaction typically takes place in dry, aprotic solvents such as diethyl ether (Et₂O) or tetrahydrofuran (THF), which do not interfere with the highly reactive organolithium species.
  • Carbon-Carbon Bond Formation: This reaction is invaluable for synthesizing complex molecules because it efficiently forms new carbon-carbon bonds, extending the carbon skeleton of the starting material.

For a deeper understanding of this important organic chemistry transformation, you can explore resources on organolithium reagents and nucleophilic addition reactions.