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How do you calculate pseudo rate?

Published in Chemical Kinetics 5 mins read

The pseudo rate, more precisely known as the pseudo-first-order rate constant (k_obs), is calculated to simplify the kinetics of a complex reaction by making it appear first-order with respect to a single reactant. This simplification occurs when one or more reactants are present in significantly larger concentrations than the reactant of interest, effectively keeping their concentrations constant throughout the reaction.


Understanding Pseudo-First-Order Reactions

Many chemical reactions involve multiple reactants. Determining the true rate law can be complicated, especially if the reaction order with respect to each reactant is unknown or difficult to measure directly. Pseudo-first-order kinetics offers a powerful method to simplify this. By setting the concentration of all but one reactant to a large excess, their concentrations change negligibly during the course of the reaction. This makes the reaction rate effectively dependent only on the concentration of the limiting reactant, thus appearing as a first-order reaction, even if its true order is different.

For example, in a reaction A + B → Products, if [B] is much greater than [A], the concentration of B will remain nearly constant. The rate law, which might originally be Rate = k[A]^x[B]^y, simplifies to Rate = k'[A]^x, where k' = k[B]^y_initial. If x is 1, then it becomes a pseudo-first-order reaction with respect to A. Learn more about the general concept of pseudo-order reactions for further detail.

Calculating the Pseudo-First-Order Rate Constant (k_obs)

The pseudo-first-order rate constant (k_obs) can be calculated from experimental data by monitoring the concentration of the limiting reactant over time, assuming the reaction behaves as a first-order process under the chosen conditions.

The Formula

For a reaction that exhibits pseudo-first-order kinetics with respect to a reactant A, the observed rate constant (k_obs) can be calculated using the integrated rate law for a first-order reaction:

kobs = -ln([A]t / [A]0) / t

Where:

  • kobs is the pseudo-first-order rate constant (units typically s⁻¹, min⁻¹, or hr⁻¹).
  • [A]t is the concentration of the reactant A at a specific time t.
  • [A]0 is the initial concentration of the reactant A (at time t = 0).
  • t is the time elapsed between the initial measurement and the measurement of [A]t.

This formula is derived directly from the integrated rate law for a first-order reaction, ln[A]t - ln[A]0 = -kobs * t, rearranged to solve for kobs.

Steps for Calculation

To calculate kobs:

  1. Identify the limiting reactant: This is the reactant whose concentration you will monitor and which is not in large excess.
  2. Set up experimental conditions: Ensure all other reactants are present in concentrations at least 10-20 times greater than the limiting reactant.
  3. Measure initial concentration ([A]0): Determine the concentration of the limiting reactant at the start of the reaction (t=0).
  4. Measure concentration at time t ([A]t): Monitor the concentration of the limiting reactant at various time points during the reaction.
  5. Select a data point: Choose a pair of [A]t and t values.
  6. Apply the formula: Substitute [A]t, [A]0, and t into the equation kobs = -ln([A]t / [A]0) / t to calculate kobs.
  7. Average multiple calculations: For greater accuracy, calculate kobs at several time points or use a graphical method (e.g., plotting ln[A]t vs. t to find the slope -kobs).

Example Calculation

Consider a reaction where reactant A is consumed. We have the following experimental data, with reactant B in large excess:

Time (s) [A] (M)
0 0.100
60 0.082
120 0.067

Let's calculate kobs using the data point at t = 60 s:

  • [A]0 = 0.100 M
  • [A]t = 0.082 M (at t = 60 s)

Using the formula:
kobs = -ln([A]t / [A]0) / t
kobs = -ln(0.082 M / 0.100 M) / 60 s
kobs = -ln(0.82) / 60 s
kobs = -(-0.1985) / 60 s
kobs = 0.1985 / 60 s
kobs ≈ 0.00331 s⁻¹

If we use the data point at t = 120 s:

  • [A]0 = 0.100 M
  • [A]t = 0.067 M (at t = 120 s)

kobs = -ln(0.067 M / 0.100 M) / 120 s
kobs = -ln(0.67) / 120 s
kobs = -(-0.4005) / 120 s
kobs = 0.4005 / 120 s
kobs ≈ 0.00334 s⁻¹

The consistency in kobs values confirms the pseudo-first-order behavior under these conditions.

When to Use Pseudo-First-Order Kinetics

This approach is particularly useful in several scenarios:

  • Simplifying Complex Reactions: When a reaction involves multiple reactants, and determining the individual reaction orders is difficult.
  • Understanding Specific Reactant Behavior: To study the kinetics of a particular reactant in isolation without interference from concentration changes of other reactants.
  • Enzyme Kinetics: Often used in biochemistry where substrates are present in excess relative to the enzyme, making the reaction pseudo-first-order with respect to the substrate (at low substrate concentrations) or zero-order (at high substrate concentrations).
  • Reaction Mechanism Elucidation: Helps in identifying elementary steps and rate-determining steps by isolating the effect of individual reactant concentrations.
  • Batch Reactor Design: For predicting reaction rates in industrial processes where one reactant is intentionally kept in excess.

Importance and Applications

Calculating the pseudo-first-order rate constant is a cornerstone technique in chemical kinetics. It allows researchers and engineers to accurately determine reaction rates under simplified, controlled conditions, which can then be extrapolated to more complex systems. This method is crucial in fields ranging from pharmaceutical development (e.g., drug degradation studies), environmental chemistry (e.g., pollutant degradation), and materials science to understanding fundamental reaction mechanisms. It provides a practical pathway to characterizing kinetic behavior when full multi-order rate law determination is experimentally challenging or unnecessary.