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How Do I Remove a Logarithm from an Equation?

Published in Solving Logarithmic Equations 4 mins read

To remove a logarithm from an equation, the most direct and fundamental method is to raise both sides of the equation to the same exponent as the base of the logarithm. This action effectively "undoes" the logarithmic operation, allowing you to solve for the variable.

Understanding the Inverse Relationship

Logarithms and exponentiation are inverse operations. This means that one operation can cancel out the other. For example, if you have log_b(x) = y, it can be rewritten in its equivalent exponential form as b^y = x. The process of "removing" a logarithm from an equation is essentially converting it back into its exponential form.

Step-by-Step Guide to Eliminating Logarithms

Follow these steps to successfully remove logarithms from an equation:

  1. Isolate the Logarithmic Term: If your equation contains multiple terms, first collect all logarithmic terms on one side of the equation. Any non-logarithmic terms should be moved to the other side.
  2. Simplify Logarithmic Expressions: If you have multiple logarithm terms on one side, simplify them into a single logarithm using the properties of logarithms.
    • Product Rule: log_b(M) + log_b(N) = log_b(MN)
    • Quotient Rule: log_b(M) - log_b(N) = log_b(M/N)
    • Power Rule: p * log_b(M) = log_b(M^p)
      You can learn more about these logarithm properties from reputable educational sources.
  3. Identify the Base: Determine the base of the logarithm.
    • If it's written as log_b(x), the base is b.
    • If it's log(x) without a subscript, it typically implies a base of 10 (common logarithm).
    • If it's ln(x), it implies a base of e (natural logarithm).
  4. Exponentiate Both Sides: Raise both sides of the equation as an exponent to the identified base.
    • If you have log_b(expression) = value, then apply b^(log_b(expression)) = b^(value).
    • The left side will simplify to just expression, leaving you with expression = b^(value).
  5. Solve for the Variable: Once the logarithm is removed, you will have a standard algebraic equation. Solve this equation for the unknown variable.
  6. Check for Extraneous Solutions: Always verify your solutions by plugging them back into the original equation. Remember, the argument of a logarithm (the term inside the parentheses, like x in log(x)) must always be positive. Any solution that results in a negative or zero argument for a logarithm in the original equation is an extraneous solution and must be discarded.

Practical Examples

Let's look at some examples to illustrate the process:

Example 1: Simple Logarithm

Equation: log_3(x) = 2

  1. Isolate: The logarithm is already isolated on one side.
  2. Simplify: No further simplification needed.
  3. Identify Base: The base is 3.
  4. Exponentiate: Raise both sides to the power of 3:
    3^(log_3(x)) = 3^2
    This simplifies to x = 9.
  5. Solve: x = 9.
  6. Check: log_3(9) = 2 is true (3^2 = 9), and the argument (9) is positive. So, x=9 is a valid solution.

Example 2: Equation with Multiple Logarithms

Equation: log_2(x + 1) + log_2(x - 1) = 3

  1. Isolate: Logarithms are already on one side.
  2. Simplify: Use the product rule to combine the logs:
    log_2((x + 1)(x - 1)) = 3
    log_2(x^2 - 1) = 3
  3. Identify Base: The base is 2.
  4. Exponentiate: Raise both sides to the power of 2:
    2^(log_2(x^2 - 1)) = 2^3
    This simplifies to x^2 - 1 = 8.
  5. Solve:
    x^2 = 9
    x = 3 or x = -3.
  6. Check:
    • For x = 3: log_2(3 + 1) + log_2(3 - 1) = log_2(4) + log_2(2) = 2 + 1 = 3. This is a valid solution as arguments (4 and 2) are positive.
    • For x = -3: log_2(-3 + 1) + log_2(-3 - 1) = log_2(-2) + log_2(-4). Since the arguments (-2 and -4) are negative, x = -3 is an extraneous solution and must be discarded.
      The only valid solution is x = 3.

Example 3: Natural Logarithm

Equation: ln(x - 4) = 5

  1. Isolate: The logarithm is isolated.
  2. Simplify: No further simplification.
  3. Identify Base: ln means the base is e.
  4. Exponentiate: Raise both sides to the power of e:
    e^(ln(x - 4)) = e^5
    This simplifies to x - 4 = e^5.
  5. Solve:
    x = e^5 + 4. (Using a calculator, e^5 is approximately 148.41, so x is about 152.41).
  6. Check: x - 4 = e^5 is positive, so the argument is valid.

Summary of Logarithm Properties

Understanding these properties is crucial for simplifying logarithmic expressions before removing them.

Property Name Rule
Product Rule log_b(MN) = log_b(M) + log_b(N)
Quotient Rule log_b(M/N) = log_b(M) - log_b(N)
Power Rule log_b(M^p) = p * log_b(M)
Change of Base log_b(M) = log_c(M) / log_c(b)

By following these steps and understanding the inverse relationship between logarithms and exponentiation, you can effectively remove logarithms from equations and solve for unknown variables.